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Proof step 1 from proof mult-ls-03 (conclusion)

n ≠ 0 ⊦ i0 < i / n→i(n) → i0 * n→i(n) < i

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 2:
i0 < i / n→i(n), i ≤ i0 * n→i(n) ⊦ n = 0

Rule argument

Additional information

Used simplifier rules: lels: ⊦ ¬ i < j ↔ j ≤ i; from specification int-abs