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Proof step 1 from proof n2i-01 (conclusion)

⊦ n→i(1) = 1

User applied rule insert lemma

And obtained the following new goals

Proof step 2:
⊦ n→i(n +1) = n→i(n) +1

Rule argument

spec: intnat inst: name: Nat2int-succ seq: ⊦ n→i(n +1) = n→i(n) +1 subst: [n] → [0] flags: current, []

Additional information

Used terms: 0