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Proof step 1 from proof n2i-sub (conclusion)

⊦ n ≤ m → n→i(m - n) = n→i(m) - n→i(n)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 2:
n ≤ m ⊦ n→i(m) = n→i(m - n) + n→i(n)

Rule argument

Additional information

Used simplifier rules: sub-eq: ⊦ i - j = i0 ↔ i = i0 + j; from specification int-abs