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Proof step 2 from proof nat (previous step)

i < 0, j ≠ 0 ⊦ i→n(i) / i→n(j) = i→n(i / j)

User applied rule cut formula

And obtained the following new goals

Proof step 3:
j < 0, i < 0, j ≠ 0 ⊦ i→n(i) / i→n(j) = i→n(i / j)
Proof step 5:
i < 0, j ≠ 0 ⊦ j < 0, i→n(i) / i→n(j) = i→n(i / j)

Rule argument

fma: j < 0

Additional information

Used formulas: j < 0