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Proof step 2 from proof nat2int-04 (
previous step
)
⊦ n→i(m) < n→i(n) ↔ m < n
User applied rule insert rewrite lemma
And obtained the following new goals
Proof step 3
:
⊦ ¬ m < n ↔ n ≤ m
Proof step 4
:
⊦ n→i(m) < n→i(n) ↔ ¬ n ≤ m
Rule argument
spec: nat inst: name: lels seq: ⊦ ¬ m < n ↔ n ≤ m subst: [n, m] → [n, m] flags: rewrite
Additional information
Used terms: n, m