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Proof step 2 from proof num-n2i-eq (previous step)

0 ≤ i ⊦ n→i(n) = i ↔ n = i→n(i)

Heuristic simplifier applied rule simplifier

And closed the goal!

Rule argument

Additional information

Used simplifier rules: n2n: ⊦ i→n(n→i(n)) = n;%i2i-pos-01: ⊦ 0 ≤ i → n→i(i→n(i)) = i;