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Proof step 1 from proof elim-list (conclusion)

⊦ x ≠ [] → (a = x.first ∧ y = x.rest ↔ x = a + y)

Heuristic simplifier applied rule simplifier

And closed the goal!

Rule argument

Additional information

Used simplifier rules: fr-02: ⊦ x ≠ [] → x.first + x.rest = x;%sel-1: ⊦ (a + x).first = a;%sel-2: ⊦ (a + x).rest = x;