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Proof step 1 from proof fr-04 (conclusion)

⊦ x.first = y.first → x.rest = y.rest → x = y ∨ x = [] ∨ y = []

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 2:
x.rest = y.rest, x.first = y.first ⊦ x = y, x = [], y = []

Rule argument

Additional information