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Proof step 1 from proof lr-05 (conclusion)

⊦ ¬ # x.rest + 1 < # x

Heuristic simplifier applied rule simplifier

And closed the goal!

Rule argument

Additional information

Used simplifier rules: l: ⊦ # x = 0 ↔ x = [];%length-rest: ⊦ x ≠ [] → # x.rest = (# x)-1;%c: ⊦ m + n = n + m; from specification nat-basic2%a: ⊦ (m + n0) + n1 = m + n0 + n1; from specification nat-basic2%sub-ls: ⊦ ¬ n + (m - n) < m; from specification nat%pred-03: ⊦ n -1 = n - 1; from specification nat%f: ⊦ m < n → n ≠ 0; (forward) from specification nat-basic1