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Proof step 4 from proof app-01 (previous step)

∀ y, a. (x0 + y) -1l a = x0 + (y -1l a) ∨ a ∈ x0 ⊦ a = a0, (x0 + y) -1l a = x0 + (y -1l a), a ∈ x0

Heuristic quantifier closing applied rule all left

And closed the goal!

Rule argument

pos: left 1 terms: y, a

Additional information

Used terms: y, a