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Proof step 10 from proof blastN-firstN (previous step)

n ≤ # x0, ∀ n. n ≤ # x0 → butlastn(n, x0) = firstn(# x0 - n, x0) ⊦ 1 + # x0 = n, butlastn(n, a ' + x0) = a ' + firstn(# x0 - n, x0)

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 11:
⊦ n ≤ # x → butlastn(n, a ' + x) = a ' + butlastn(n, x)
Proof step 12:
n ≤ # x0, n ≤ # x0, ∀ n. n ≤ # x0 → butlastn(n, x0) = firstn(# x0 - n, x0) ⊦ 1 + # x0 = n, a ' + butlastn(n, x0) = a ' + firstn(# x0 - n, x0)

Rule argument

spec: list-last inst: name: blastN-rec-01 seq: ⊦ n ≤ # x → butlastn(n, a ' + x) = a ' + butlastn(n, x) subst: [x, a, n] → [x0, a, n] flags: rewrite

Additional information

Used terms: x0, a, n