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Proof step 7 from proof blastN-firstN (previous step)

∀ n. n ≤ # x0 → butlastn(n, x0) = firstn(# x0 - n, x0) ⊦ butlastn(# x0, (a ' + x0).butlast) = []

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 8:
n = # x ⊦ butlastn(n, x) = []

Rule argument

spec: list-last inst: name: blastN-all-01 seq: n = # x ⊦ butlastn(n, x) = [] subst: [x, n] → [(a ' + x0).butlast, # x0] flags: rewrite

Additional information

Used simplifier rules: butlast-len: ⊦ # (a ' + x).butlast = # x; from specification list-last%a: ⊦ (x + y) + z = x + y + z; from specification list Used terms: (a ' + x0).butlast, # x0