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Proof step 6 from proof del-del1-nodups (previous step)

∀ a1. x0 -l a1 = x0 -1l a1 ⊦ a = a0, x0 -l a = x0 -1l a, a0 ∈ x0, dups(x0)

Heuristic quantifier closing applied rule all left

And closed the goal!

Rule argument

pos: left 1 terms: a

Additional information

Used terms: a