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Proof step 6 from proof del-del1-switch (previous step)

∀ a, b. (x0 -1l a) -l b = (x0 -l b) -1l a ∨ a = b ⊦ a = a0, a = b, (a0 ' + (x0 -1l a)) -l b = ((a0 ' + x0) -l b) -1l a

Heuristic cut applied rule cut formula

And obtained the following new goals

Proof step 7:
b = a0, ∀ a, b. (x0 -1l a) -l b = (x0 -l b) -1l a ∨ a = b ⊦ a = a0, a = b, (a0 ' + (x0 -1l a)) -l b = ((a0 ' + x0) -l b) -1l a
Proof step 9:
∀ a, b. (x0 -1l a) -l b = (x0 -l b) -1l a ∨ a = b ⊦ b = a0, a = a0, a = b, (a0 ' + (x0 -1l a)) -l b = ((a0 ' + x0) -l b) -1l a

Rule argument

fma: b = a0

Additional information

Used formulas: b = a0