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Proof step 1 from proof del-n-simp (conclusion)
a ≠ b ⊦ ((* a) ' + x) -l (* b) = a ' + (x -l b)
Special step normalize
And obtained the following new goals
Proof step 2
:
a ≠ b ⊦ (a ' + x) -l b = a ' + (x -l b)