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Proof step 14 from proof del-rev (previous step)

¬ a ∈ a0 ', ∀ a. rev(x0) -l a = rev(x0 -l a) ⊦ a = a0, (rev(x0) -l a) + a0 ' = rev(x0 -l a) + a0 '

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 15:
∀ a. rev(x0) -l a = rev(x0 -l a) ⊦ a = a0, rev(x0) -l a = rev(x0 -l a)

Rule argument

Additional information

Used simplifier rules: in-17: ⊦ a ∈ b ' ↔ a = b; from specification list%a: ⊦ (x + y) + z = x + y + z; from specification list%app-03: ⊦ x + y = z + y ↔ x = z; from specification list