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Proof step 3 from proof del1-del-switch (previous step)

∀ a, b. (x0 -l a) -1l b = (x0 -1l b) -l a ∨ a = b ⊦ ((a0 + x0) -l a) -1l b = ((a0 + x0) -1l b) -l a, a = b

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 4:
∀ a, b. (x0 -l a) -1l b = (x0 -1l b) -l a ∨ a = b ⊦ a = b, ((a0 ' + x0) -l a) -1l b = ((a0 ' + x0) -1l b) -l a

Rule argument

Additional information

Used simplifier rules: c: ⊦ a + x = a ' + x; from specification list