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Proof step 1 from proof dups-01 (conclusion)
⊦ ¬ dups(y) → ¬ b ∈ y -1l b
Heuristic simplifier applied rule simplifier
And obtained the following new goals
Proof step 2
:
b ∈ y -1l b, b ∈ y ⊦ dups(y)
Rule argument
Additional information
Used simplifier rules: in-01-01: ⊦ a ∈ x -1l b → a ∈ x;