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Proof step 4 from proof dups-01 (previous step)

b ∈ (a ' + y0) -1l b, ∀ b0. ¬ b0 ∈ y0 -1l b0 ∨ ¬ b0 ∈ y0, b = a ∨ b ∈ y0 ⊦ dups(y0), a ∈ y0

Heuristic cut applied rule cut formula

And obtained the following new goals

Proof step 5:
b ∈ (a ' + y0) -1l b, ∀ b0. ¬ b0 ∈ y0 -1l b0 ∨ ¬ b0 ∈ y0, b = a ∨ b ∈ y0 ⊦ b = a, dups(y0), a ∈ y0

Rule argument

fma: b = a

Additional information

Used simplifier rules: del1-y: ⊦ (a ' + x) -1l a = x;%a: ⊦ (x + y) + z = x + y + z; from specification list Used formulas: b = a