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Proof step 1 from proof dups-first-last-split (conclusion)

⊦ n ≤ # x → (dups(x) ↔ dups(firstn(n, x) + lastn(# x - n, x)))

User applied rule insert rewrite lemma

And obtained the following new goals

Rule argument

spec: list-del inst: name: firstn-last-eq seq: ⊦ n ≤ # x → firstn(n, x) + lastn(# x - n, x) = x subst: [x, n] → [x, n] flags: rewrite, current

Additional information

Used terms: x, n