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Proof step 10 from proof extension (previous step)

# y = # y0, n < # y0, ∀ n0. ¬ # y0 < n0 → (a ' + y)[n0] = (a ' + y0)[n0] ⊦ y[n] = y0[n], y0 = []

User applied rule all left

And closed the goal!

Rule argument

pos: left 3 terms: n + 1 abort: F discard: F computed: F

Additional information

Used simplifier rules: get-succ: ⊦ (a ' + x)[n + 1] = x[n];%s: ⊦ m < n + 1 ↔ ¬ n < m; from specification nat-basic2%a: ⊦ (m + n0) + n1 = m + n0 + n1; from specification nat-basic2%c: ⊦ m + n = n + m; from specification nat-basic2%a: ⊦ (x + y) + z = x + y + z; from specification list Used terms: n + 1