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Proof step 2 from proof firstN-dups-01 (previous step)

n < # y, dups(x + firstn(n, y)) ⊦ y = [], dups(y), dups(x), dups(x + y)

User applied rule insert rewrite lemma

And obtained the following new goals

Rule argument

spec: list-del inst: name: firstN-dups-03 seq: ⊦ n ≤ # y ∧ ¬ dups(x + y) → ¬ dups(x + firstn(n, y)) subst: [y, n, x] → [y, n, x] flags: rewrite, current

Additional information

Used simplifier rules: lels-03: ⊦ m < n → m ≤ n; from specification nat Used terms: y, n, x