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Proof step 2 from proof firstN-dups-05 (previous step)

n < # x, dups(firstn(n, x)) ⊦ x = [], dups(x)

User applied rule insert rewrite lemma

And obtained the following new goals

Rule argument

spec: list-del inst: name: firstN-dups-04 seq: ⊦ n ≤ # x ∧ ¬ dups(x) → ¬ dups(firstn(n, x)) subst: [x, n] → [x, n] flags: rewrite, current

Additional information

Used simplifier rules: lels-03: ⊦ m < n → m ≤ n; from specification nat Used terms: x, n