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Proof step 1 from proof firstN-lastN-in (conclusion)

⊦ n ≤ # x ∧ a ∈ x ∧ ¬ a ∈ lastn(n, x) → (¬ a ∈ firstn(# x - n, x) ↔ false)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 2:
n ≤ # x, a ∈ x ⊦ a ∈ lastn(n, x), a ∈ firstn(# x - n, x)

Rule argument

Additional information