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Proof step 5 from proof firstN-lastN-in (previous step)

firstn(# x - n, x) + lastn(n, x) = x, n ≤ # x, a ∈ x ⊦ a ∈ lastn(n, x), a ∈ firstn(# x - n, x)

User applied rule insert equation

And obtained the following new goals

Proof step 6:
n ≤ # x, a ∈ firstn(# x - n, x) + lastn(n, x) ⊦ a ∈ lastn(n, x), a ∈ firstn(# x - n, x)

Rule argument

pos: left 1 flags: rotate, discard, [[1,3,2]]

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