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Proof step 6 from proof firstN-lastN (previous step)

n ≤ # x, # x = n0 + n ⊦ firstn(n0, x) + restn(# x - n, x) = x

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 7:
# x = n0 + n ⊦ firstn(n0, x) + restn(n0, x) = x

Rule argument

Additional information

Used simplifier rules: lep: ⊦ m ≤ m + n; from specification nat%c: ⊦ m + n = n + m; from specification nat-basic2%a: ⊦ (m + n0) + n1 = m + n0 + n1; from specification nat-basic2%eq-01: ⊦ m + n - m = n; from specification nat