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Proof step 1 from proof firstn-last (conclusion)

⊦ m ≠ 0 ∧ m ≤ # x → firstn(m, x).last = x[m -1]

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 2:
m ≤ # x ⊦ m = 0, firstn(m, x).last = x[m - 1]

Rule argument

Additional information

Used simplifier rules: pred-03: ⊦ n -1 = n - 1; from specification nat