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Proof step 2 from proof from-notin (previous step)

⊦ frome(x, a) = [], a ∈ x

Heuristic structural induction applied rule structural induction

And obtained the following new goals

Proof step 3:
∀ a. frome(x0, a) = [] ∨ a ∈ x0 ⊦ frome(a0 + x0, a) = [], a ∈ a0 + x0

Rule argument

term: x

Additional information

Used simplifier rules: fromE-empty: ⊦ frome([], a) = [];%list freely generated by [], +;;