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Proof step 5 from proof get-last-04 (previous step)

# x ≠ 0 ⊦ x = [], (x + y)[(# x)-1] = x.last

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 6:
⊦ x = [], (x + y)[# x - 1] = x.last

Rule argument

Additional information

Used simplifier rules: l: ⊦ # x = 0 ↔ x = []; from specification list-data%pred-03: ⊦ n -1 = n - 1; from specification nat