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Proof step 6 from proof get-last-nonempty (previous step)

⊦ (a ' + x0)[# x0] = (a ' + x0).last

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 7:
⊦ (a ' + x)[# x] = (a ' + x).last

Rule argument

spec: inst: name: get-last2 seq: ⊦ (a ' + x)[# x] = (a ' + x).last subst: [x, a] → [x0, a] flags: rewrite, current

Additional information

Used terms: x0, a