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Proof step 6 from proof get-restn (
previous step
)
m + n0 < # y, ∀ m, x. m + n0 < # x → restn(n0, x)[m] = x[m + n0] ∨ x = [] ⊦ restn(n0, y)[m] = y[m + n0], y = []
Heuristic quantifier closing applied rule all left
And closed the goal!
Rule argument
pos: left 2 terms: m, y
Additional information
Used terms: m, y