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Proof step 1 from proof in-05 (conclusion)

⊦ ¬ a ∈ y -1l b ∧ a ∈ y → a = b

Heuristic simplifier applied rule simplifier

And closed the goal!

Rule argument

Additional information

Used simplifier rules: in-04: ⊦ a ∈ x ∧ a ≠ b → a ∈ x -1l b;