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Proof step 2 from proof lastN-dups-01 (previous step)

dups(lastn(n, x)), n ≤ # x ⊦ dups(x)

User applied rule insert rewrite lemma

And obtained the following new goals

Rule argument

spec: list-del inst: name: lastN-dups seq: ⊦ ¬ dups(x) ∧ n < # x → ¬ dups(lastn(n, x)) subst: [x, n] → [x, n] flags: rewrite, current

Additional information

Used simplifier rules: lastN-all: ⊦ n = # x → lastn(n, x) = x;%lels: ⊦ ¬ m < n ↔ n ≤ m; from specification nat%anti: ⊦ m ≤ n → (n ≤ m ↔ m = n); from specification nat Used terms: x, n