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Proof step 2 from proof lastn-app (previous step)

# y ≤ n ⊦ lastn(n, x + y) = lastn(n - # y, x) + y

Heuristic elimination applied rule insert elim lemma

And obtained the following new goals

Proof step 3:
n = n0 + # y, # y ≤ n ⊦ lastn(n, x + y) = lastn(n0, x) + y

Rule argument

spec: nat inst: name: elim-sub seq: n ≤ m ⊦ n0 = m - n ↔ m = n0 + n subst: [m, n, n0] → [n, # y, n0] flags:

Additional information

Used simplifier rules: n ≤ m ⊦ n0 = m - n ↔ m = n0 + n; (elim) Used terms: n, # y, n0