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Proof step 2 from proof lastn-lastn-01 (previous step)

m ≤ n ⊦ lastn(m, lastn(n, x)) = lastn(m, x)

User applied rule structural induction

And obtained the following new goals

Proof step 3:
∀ n, x. m0 ≤ n → lastn(m0, lastn(n, x)) = lastn(m0, x), m0 +1 ≤ n ⊦ lastn(m0 +1, lastn(n, x)) = lastn(m0 +1, x)

Rule argument

indvar: m

Additional information

Used simplifier rules: lastN-zero: ⊦ lastn(0, x) = [];%nat freely generated by 0, +1;;