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Proof step 6 from proof lastn-length (
previous step
)
∀ x. # lastn(n0, x) = n0 ⊦ # lastn(n0, x.butlast) = n0
Heuristic quantifier closing applied rule all left
And closed the goal!
Rule argument
pos: left 1 terms: x.butlast
Additional information
Used terms: x.butlast