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Proof step 6 from proof lastn-mklist (previous step)

m < # mklist(a, n0 + 1), m ≤ n0 + 1, ∀ m, a. m ≤ n0 → lastn(m, mklist(a, n0)) = mklist(a, m) ⊦ lastn(m, mklist(a, n0 + 1).rest) = mklist(a, m)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 7:
m ≤ n0 + 1, m ≤ n0, ∀ m, a. m ≤ n0 → lastn(m, mklist(a, n0)) = mklist(a, m) ⊦ lastn(m, mklist(a, n0 + 1).rest) = mklist(a, m)

Rule argument

Additional information

Used simplifier rules: lels: ⊦ ¬ m < n ↔ n ≤ m; from specification nat%c: ⊦ m + n = n + m; from specification nat-basic2%a: ⊦ (m + n0) + n1 = m + n0 + n1; from specification nat-basic2%s: ⊦ m < n + 1 ↔ ¬ n < m; from specification nat-basic2%mk-len: ⊦ # mklist(a, n) = n; from specification list-last