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Proof step 1 from proof lastn-neq-02 (conclusion)

⊦ # y ≠ n → lastn(n + 1, x) ≠ a ' + y

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 2:
lastn(n + 1, x) = a ' + y ⊦ # y = n

Rule argument

Additional information

Used simplifier rules: in-rec: ⊦ a ∈ b ' + x ↔ ¬ ¬(a = b ∨ a ∈ x); from specification list%a: ⊦ (x + y) + z = x + y + z; from specification list%in-14: ⊦ a ' + x = y → a ∈ y; (forward) from specification list