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Proof step 1 from proof lastn-neq-04 (conclusion)

⊦ n ≤ # x ∧ b ∈ y ∧ ¬ b ∈ x → lastn(n, x) ≠ a ' + y

Heuristic simplifier applied rule simplifier

And closed the goal!

Rule argument

Additional information

Used simplifier rules: lastn-neq-01: ⊦ n ≤ # x ∧ a ∈ y ∧ ¬ a ∈ x → lastn(n, x) ≠ b ' + y;%a: ⊦ (x + y) + z = x + y + z; from specification list