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Proof step 12 from proof lastn-restn-01 (previous step)

n0 ≤ # y, # y = n0 + n1, ∀ x, n0. # x = n0 + n1 → lastn(n1, x) = restn(n0, x) ⊦ lastn(n1, y) + a ' = restn(n0, y) + a '

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

Additional information

Used simplifier rules: c: ⊦ m + n = n + m; from specification nat-basic2%a: ⊦ (m + n0) + n1 = m + n0 + n1; from specification nat-basic2%lep: ⊦ m ≤ m + n; from specification nat%a: ⊦ (x + y) + z = x + y + z; from specification list%app-03: ⊦ x + y = z + y ↔ x = z; from specification list