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Proof step 3 from proof lastn-restn-01 (previous step)

# x = n0 + n ⊦ lastn(n, x) = restn(n0, x)

User applied rule structural induction

And obtained the following new goals

Proof step 4:
∀ x, n0. # x = n0 + n1 → lastn(n1, x) = restn(n0, x), # x = n0 + n1 +1 ⊦ lastn(n1 +1, x) = restn(n0, x)

Rule argument

indvar: n

Additional information

Used simplifier rules: lastN-zero: ⊦ lastn(0, x) = [];%rest-empty: ⊦ # x = n → restn(n, x) = [];%nat freely generated by 0, +1;;%add-base: ⊦ n + 0 = n; from specification nat-basic2%a: ⊦ (m + n0) + n1 = m + n0 + n1; from specification nat-basic2%c: ⊦ m + n = n + m; from specification nat-basic2