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Proof step 7 from proof lastn-restn-01 (previous step)

# x = n0 + n1 + 1, ∀ x, n0. # x = n0 + n1 → lastn(n1, x) = restn(n0, x) ⊦ lastn(n1, x.butlast) + x.last = restn(n0, x)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 8:
# x = n0 + n1 + 1, ∀ x, n0. # x = n0 + n1 → lastn(n1, x) = restn(n0, x) ⊦ lastn(n1, x.butlast) + x.last ' = restn(n0, x)

Rule argument

Additional information

Used simplifier rules: Last: ⊦ x + a = x + a '; from specification list