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Proof step 12 from proof lastn-restn (previous step)

m + m0 ≤ # x0, m ≤ # x0, ∀ m, n. m + n ≤ # x0 → lastn(m, restn(n, x0)) = lastn(m, x0) ⊦ lastn(m, restn(m0, x0)) = lastn(m, x0)

Heuristic quantifier closing applied rule all left

And closed the goal!

Rule argument

pos: left 3 terms: m, m0

Additional information

Used terms: m, m0