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Proof step 1 from proof one-03 (conclusion)

⊦ a '[0] = a

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 2:
⊦ x ≠ [] → x[0] = x.first

Rule argument

spec: list-del inst: name: get-zero seq: ⊦ x ≠ [] → x[0] = x.first subst: [x] → [a '] flags: rewrite, current

Additional information

Used simplifier rules: first: ⊦ a '.first = a; from specification list%e: ⊦ a ' ≠ []; from specification list Used terms: a '