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Proof step 1 from proof pos-equal (conclusion)

⊦ a ∈ x ∧ pos(a, x) = n → (pos(b, x) = n ↔ a = b)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 2:
pos(b, x) = pos(a, x), a ∈ x ⊦ a = b

Rule argument

Additional information