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Proof step 8 from proof put-at-eq (previous step)

m0 < # x0, ∀ m, a. m < # x0 → x0[m, a][m] = a ⊦ x0[m0, a][m0] = a, x0 = []

Heuristic quantifier closing applied rule all left

And closed the goal!

Rule argument

pos: left 2 terms: m0, a

Additional information

Used terms: m0, a