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Proof step 18 from proof put-at (previous step)

m0 < # x0, ∀ m, n, a. m < # x0 → m ≠ n → x0[m, a][n] = x0[n] ⊦ m0 = m1, x0 = [], x0[m0, a][m1] = x0[m1]

Heuristic quantifier closing applied rule all left

And closed the goal!

Rule argument

pos: left 2 terms: m0, m1, a

Additional information

Used terms: m0, m1, a