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Proof step 8 from proof put-in (previous step)

m0 < # x0, ∀ a, m, b. a ≠ x0[m] ∧ m < # x0 → (a ∈ x0[m, b] ↔ a = b ∨ a ∈ x0) ⊦ a = x0[m0], a = a0, a ∈ x0[m0, b] ↔ a = b ∨ a ∈ x0, x0 = []

User applied rule all left

And closed the goal!

Rule argument

pos: left 2 terms: a, m0, b abort: F discard: F computed: T

Additional information

Used terms: a, m0, b