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Proof step 2 from proof put-rec-01 (previous step)

⊦ x = [], n = 0, x[n, a] = x.first ' + x.rest[n - 1, a]

Heuristic elimination applied rule insert elim lemma

And obtained the following new goals

Proof step 3:
n = m + 1 ⊦ x = [], n = 0, x[n, a] = x.first ' + x.rest[m, a]

Rule argument

spec: nat inst: name: elim-pred-c seq: n ≠ 0 ⊦ m = n - 1 ↔ n = m + 1 subst: [n, m] → [n, m] flags:

Additional information

Used simplifier rules: n ≠ 0 ⊦ m = n - 1 ↔ n = m + 1; (elim) Used terms: n, m