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Proof step 1 from proof restn-apprec (conclusion)

⊦ restn(m, restn(n, x)) = restn(m + n, x)

Heuristic structural induction applied rule structural induction

And obtained the following new goals

Proof step 2:
∀ m, x. restn(m, restn(n0, x)) = restn(m + n0, x) ⊦ restn(m, restn(n0 +1, x)) = restn(m + n0 +1, x)

Rule argument

term: n

Additional information

Used simplifier rules: restN-zero: ⊦ restn(0, x) = x;%nat freely generated by 0, +1;;%add-base: ⊦ n + 0 = n; from specification nat-basic2%a: ⊦ (m + n0) + n1 = m + n0 + n1; from specification nat-basic2%c: ⊦ m + n = n + m; from specification nat-basic2